28x^2=192

Solution for 28x^2=192 equation:

28x^2=192

We move all terms to the left:

28x^2-(192)=0

a = 28; b = 0; c = -192;
Δ = b2-4ac
Δ = 02-4·28·(-192)
Δ = 21504
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{21504}=\sqrt{1024*21}=\sqrt{1024}*\sqrt{21}=32\sqrt{21}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32\sqrt{21}}{2*28}=\frac{0-32\sqrt{21}}{56}
=-\frac{32\sqrt{21}}{56}
=-\frac{4\sqrt{21}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32\sqrt{21}}{2*28}=\frac{0+32\sqrt{21}}{56}
=\frac{32\sqrt{21}}{56}
=\frac{4\sqrt{21}}{7}
$